Question

help! limits!

Answer 1

\[\lim_{x \rightarrow 0} (1-cosx)/x^2\]

Answer 2

multiply with (1+ cos x)/(1 + cos x) and use the sin x/x -> 1 as x tends to zero

Answer 3

1st step :by applying l'hopital rule it will be limx→0((1−cosx)/x)/(x2/x)
so it will be limx→0(sinx)/2x,
2nd step take half out so it will be : 1/2limx→0 sinx\x
3rd aproch to zero : 1/2 limx→0 (c0sx)
the final answer is 1/2

Answer 4

Eyad - where exactly does this zero come from?

Answer 5

the zero come from the tendency ,and the under the limit u fint x tends to ... ,and in this equation x→0 ..

Answer 6

and does sinx/x = cosx

Answer 7

finds

Answer 8

ok i see that part now

Answer 9

sinx\x =1 ,and cos(0)=1

Answer 10

thats good :)

Answer 11

so you just made sinx/x =1 then turned that one into cosine

Answer 12

yes ,thats right .

Answer 13

if you didnt want to have to look at it that way would it also have been correct to take the 1/2(1) and done it this way

Answer 14

yea because u separated the half from the lim ,so at anyway it would give half .

Answer 15

ok

Answer 16

ok,I g2g now bye