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How do I take the take the integral of an absolute value?
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the integral in geometric means is the area under the curve. that and absolute value functions are actually piecewise functions in R^2 space
|x| = sqrt(x)^2
|x+1| is equivalent to -(x+1) x < -1 (x+1) x > -1
\[\int\limits_{-2}^{-1} -(x+1) dx\] + \[\int\limits\limits_{-1}^{1} x+1 dx\] should give you your answer
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\[\int (\sqrt{x+1})^2dx\]
alexs might be simpler tho
okay, thanks!
i was thinking derivatives fer some reason ;)
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