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Mathematics 15 Online
OpenStudy (anonymous):

How do I take the take the integral of an absolute value?

OpenStudy (anonymous):

OpenStudy (anonymous):

the integral in geometric means is the area under the curve. that and absolute value functions are actually piecewise functions in R^2 space

OpenStudy (amistre64):

|x| = sqrt(x)^2

OpenStudy (anonymous):

|x+1| is equivalent to -(x+1) x < -1 (x+1) x > -1

OpenStudy (anonymous):

\[\int\limits_{-2}^{-1} -(x+1) dx\] + \[\int\limits\limits_{-1}^{1} x+1 dx\] should give you your answer

OpenStudy (amistre64):

\[\int (\sqrt{x+1})^2dx\]

OpenStudy (amistre64):

alexs might be simpler tho

OpenStudy (anonymous):

okay, thanks!

OpenStudy (amistre64):

i was thinking derivatives fer some reason ;)

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