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Chemistry 9 Online
OpenStudy (anonymous):

Calculate the freezing point and boiling point of each of the following solutions. 1) Calculate the freezing point of each of the solution 65.0g of glucose,C6H12O6 , added to 0.403kg of water. 2)Calculate the boiling point of the solution. 65.0g of glucose,C6H12O6 , added to 0.403kg of water. 3)Calculate the freezing point of each of the solution 0.200mol of sucrose,C12H22O11 , a nonelectrolyte, dissolved in 1.35kg of water. 4) Calculate the boiling point of the solution. 0.200mol of sucrose, C12H22O11, a nonelectrolyte, dissolved in 1.35kg of water.

OpenStudy (anonymous):

well it looks like you are going to need to calculatee the molality find the constant in a book somewhere and plug it into the formula that i don't have infront of me

OpenStudy (anonymous):

ΔTb = Kb · bB

OpenStudy (anonymous):

i dont know how to use that formula

OpenStudy (anonymous):

alright Kf for glocose is 1.86, can you figure out the molility?

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