Question

.

Answer 1

How would you begin?

Answer 2

horizontally stretched by 2... does that mean the latus rectum will be twice as long?

Answer 3

latus rectum? i've never heard of that term

Answer 4

if yes, then 4p(y-k) = (x-h)^2 then just multiply the by 2 to get
8p(y-k) = (x-h)^2
so your equation is
8(y+4) = (x+3)^2
you can simplify this to "y=" form if you want the standard answer.

Answer 5

@petewe, yes... we all laughed too when my teacher said the name...
http://mathworld.wolfram.com/LatusRectum.html

Answer 6

Try to graph f(x) = x^2 + a, let x be zero, then y will be in the a position. Thats the vertice, moved by a units.

For stretching uses instead of x, 2x, 3x, etc, graph and lokk for the thing you want to happen. Maybe es x/2??

For moving to the right or left let x be x+-b
so y = (x+b)

grapgh and see what you get.

Answer 7

^ that's correct, great now you have an answer and no understanding why.

Answer 8

thanks everyone.