@dpainc, Help here please?
if i can...
Thank you:)
Is this equation correct? y = 3tan(2x-60 ) - 5
Its y = 3tan(2x+60 ) - 5
the - 5 is correct, the -60 should be a + 60.
Yes, I just corrected that:)
oh, you got it before i answered.....
So does that answer the question?
lol, I know:)
what am i thinking now?
lol:)
So that answers the question right?
yeah, that's correct. you're good with this trig stuff... :)
Its people in OS like you, who helped me alot. But there are soooo many things I sitll need practice with
Can you help me with one more?
yup... sure... but i will be going back and forth with another post... hope you don't mind...
Sure:). Here is the new question.
hmmm... for that first one, i know it's translated 3 units up (if you solve for y)
the period for the first one is also shorter than the second one.... y=tanx has a period of pi(180 degrees)
and instead of increasing between vertical asymptotes, they will be decreasing... lemme check with wolf...
The -3 after y in the LHS troubles me
What happens there?
hmmm... looks like the last staement i made was incorrect. they're both increasing.
you can always make it "y = " by adding 3 to both sides in that first equation...
that's how i know it is move 3 units up...
http://www.wolframalpha.com/input/?i=y+%3D+tan%28x%29%2C+y+%3D+-tan%28-2x+%2B+180%29+%2B+3
so it becomes y = -tan( -2x + 180°)+3
Like that?
yes.
Oh. lol this time you beat me first
now, the reason i thought it was going to be decreasing was because of the -tan... when you take "-" of something, that just reflects the graph over the x axis...
There is also a reflection in the y-axis right?
omg, you beat me again:) lol
i'm getting faster.
lol. You are!
yes, there is a reflection over the y-axis... and that came from the "-"x. if it had the same sign as the y=tan(x) then i would've been correct. i missed that one.
it's that -2 is the culprit.
Ok. so There are 5 transformations taking place, correct?
No, I mean 4
y = Asin(Bx + C) + D. are these the type of equations you are looking at now?
Yes
lemme count...
the transformation steps are the a,b,c and d values. so 4
yup... i counted 4
Ok, so for a, there is a -, so there is a reflection in the yaxis
oh yeah... each of those parameters does something(transformation) to the graph...
for b, it changes the periods of the graph
no, a reflects over the x axis.
b not only changes the period but if it is negative, it reflects it over the y-axis.
OHH! okok that makes sense. sorry
and finally, d vertical translation up by 3 units
that's what d does...
Thats how I show the difference right>?
yes.... the difference between y-3 = -tan(-2x + 180) and y = tanx.
So, You are such a great teacher, I specifically look for you! Other people answer good answer but only they can understand it. I like that you explain it so that everybody understands:)
Thanks dpainc:), Btw, congrats in getting to level 61.
this is the reason why it is a good idea to just study what A, B, C, and D does to a graph of sinx, cosx, tanx, etc. if you know these basic trig graphs, you'll get a good idea of a complicated looking equation's graph without a graphing calculator.
yw. remember what i said.... you will need this when you take calculus... you're well on your way grasshopper.
Oh @dpainc, Can you check this answer? 1. State domain, range, period, vertical asymptotes, zeros, symmetry and y-intercept of: y = -2tan(3x + 180°) + 3. Answer General form of the function: -2tan(3(x-(-pi/3)))+3 • Domain: {x | all real numbers except -30 degrees +60n} • Range: {y | y is an element or R} • Period: pi/b, where b = 3. Therefore, pi/3 • Vertical Asymptotes: -0.5 and 0.5. OR –pi/6 and pi/6. • Zeroes: x = …, -1, 0, 1, 2, … (rounding off the values) • Symmetry: Since tan(-x) = - tan(x) then tan (x) is an odd function and its graph is symmetric with respect the origin(0, 3). • Y-intercept: We set x = 0 so in this case -2tan(3(0-(-pi/3)))+3 = y = 3
Vertical Asymptotes: -0.5 and 0.5. OR –pi/6 and pi/6. which is it?
They are the same thing arent they?
if you calculate them, -0.5 = -pi/6 and 0.5 = pi/6
no they're not... but if you're approximating i guess that's true but there are infinitely many vertical asymptotes
sorry man, i gotta leave. i'll check on this later ok?
Aww man, but its almost done? I have to submit this in 10 minutes:(
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