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Chemistry 14 Online
OpenStudy (anonymous):

Calculate the freezing point of each of the solution 65.0g of glucose,C6H12O6 , added to 0.403kg of water

OpenStudy (anonymous):

Can you figure out the molality?

OpenStudy (anonymous):

\[m=\frac{mole solute}{kg solvent}\]

OpenStudy (anonymous):

Yeah, its 161.29 right?

OpenStudy (anonymous):

looks really high to me how many moles do you have with 65g of glucose?

OpenStudy (anonymous):

m=.895 is what i got

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