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38.0 mL of 0.10M HCl is needed to neutralize 25.0 mL to NH4OH. What is the molarity of the ammonium hydroxide? In moles please, and work is needed.
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write balance equqation calc moles of HCl from equation calc moles of NH4OH needed calc molarity of NH4OH
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HCl + NH4OH ---> H20 + NH4Cl 38.0ml HCl (10mole HCl/100 ml HCl ) x (1mole of NH4OH/1mole HCl)=0.0038 mole NH4OH Now we divide it by .025 L to get the molartity .0038moles/025L=.152M
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