Question

points (0,0) and (3,3) lie on line k. what is the slope of the line that is perpendicular to k?

A.1
B.-1
C.0
D.Undefined

Answer 1

the answer is A.

\[slope between two points = (y_2 - y_1)/(x_2-x_1)\]
\[(3 - 0)/(3-0)\]
\[3/3\]

Answer 2

oh, perpendicular. My apologies. The slope of the line is 1. however the slope of its perpendicular is -1.

Answer 3

the production of slope of the perpendikular lines equal to -1(minus 1).
slope of the line k=(3-0)/(3-0)=3/3=1
so that the slope of the line perpendicular to k= -1

Answer 4

The line that passes through two points is..
\[\LARGE y-y_1=\underbrace{\boxed{\frac{y_2-y_1}{x_2-x_1}}}_{k}(x-x_1)\]
prependicular is :
\[\LARGE k\cdot k_1=-1\]
so we have:
\[\LARGE k=\frac33\]
hence:
\[\LARGE \frac33\cdot k_1=-1\]
\[\LARGE 1\cdot k_1=-1\]
\[\LARGE k_1=-1\]