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Mathematics 19 Online
OpenStudy (anonymous):

u=sin(x+y)+cos(x-y)

OpenStudy (anonymous):

There is no question. :(

OpenStudy (anonymous):

u=sin(x+y)+cos(x-y)= =sinxcosy+sinycosx +cosxcosy+sinxsiny= =sinx(siny+cosy)+cosx(siny+cosy)= (siny+cosy)(sinx+cosx)

OpenStudy (anonymous):

Oh, simplification! In which case @integralsabiti is right. :D

OpenStudy (anonymous):

partial derrivative

OpenStudy (anonymous):

With respect to what, \(x\) or \(y\)?

OpenStudy (anonymous):

both

OpenStudy (anonymous):

\[\frac{\partial u}{\partial x}=\cos\left(x+y\right)-\sin\left(x-y\right)\]\[\frac{\partial u}{\partial y}=\cos\left(x+y\right)+\sin\left(x-y\right)\]I know I didn't write out steps, but I'm not sure where you're confused.

OpenStudy (anonymous):

You take the derivative of the entire equation with respect to one variable, pretending the other is constant.

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