Question

y=4x^2-11x+6

Answer 1

what we have to find?

Answer 2

Find the zeros

Answer 3

I need help or examples ):

Answer 4

We can use the quadratic formula.

Answer 5

Do you know how to use it/

Answer 6

I know the formula, but I don't know how to use it.

Answer 7

Okay, no prob.

ax^2 + bx + c is the standard formula

4x^2 - 11x + 6 compare both.

a = 4
b = -11
c = 6

Now insert the values in the formula.

Answer 8

\[x=-11\pm \sqrt{-11^2-4(4)(6)}\over2(4)\]

Answer 9

just inside the radical, write (-11)^2
rest is perfect.

Answer 10

\[x=-11\pm \sqrt{11^2-4(4)(6)}\over2(4)\]

Answer 11

I'd like to note that \(-11^2\neq\left(-11\right)^2\) because \(\left(-11\right)^2=\left(-1\right)^2\left(11\right)^2\) a la \(\left(ab\right)^2=a^2b^2\) and \(-11=-1\times11\).

Answer 12

Well, that's the way the algebra we're using is defined, and understood, by most formal systems.