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Find the values of x for which the series converges: ((summation)(n=1 to infinity)) (x-1)^n/3^n
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lim of an/a(n-1) as n goes inf
\[\lim \frac{(x-1)^n}{3^n}\frac{3^{n-1}}{(x-1)^{n-1}}\] \[\lim \frac{(x-1)}{3}\] \[|\frac{x-1}{3}|\lim 1\]
I thought it was n+1??
\[|\frac{x-1}{3}|<1\] \[|x-1|<3\] -2 < x < 4
its simply next/now how you wanna represent that is up to you
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Thanks!! I understand
yw :)
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