Question

Can someone check my answer?

For y = x2 − 4x + 3,
Determine if the parabola opens up or down.
State if the vertex will be a maximum or minimum.
Find the vertex.
Find the x-intercepts.
Describe the graph of the equation.
Show all work and use complete sentences to receive full credit.

Answer 1

My Answer:

1)The parabola opens up because it is positive.

2)If a parabola open up, then we automatically know the vertex will be a minimum.

3)Find the vertex:
x = -(-4)/2(1)
=4/2
=2
y = 2^2 – 4(2) + 3
y = 4 – 8 + 3
y = -1
The vertex is (2, -1)

4)Find the x-intercepts:
0 = x^2 − 4x + 3
0 = (x -3)(x -1)
x = 3 or x = 1
The x-intercepts are (3,0) and (1,0)

5)The graph shows a symmetrical parabola with a vertex minimum below the x-axis at the point of (2,-1), halfway between the x-axis intercepts at x = 1 and x = 3, with a single, vertical axis of symmetry at x = 2.

Answer 2

You're good to go :)

Answer 3

okay, thanks :)