Question

Simplify the expression.

√-4/(5+2i)-(3+4i) The i is an imaginary #.

Answer 1

\[\sqrt{-4}/(3-2i)\]

Answer 2

sqrt of -4 is generally an impossible or undefined component of math....also an imaginary number

Answer 3

That's wrong. The choices are a) 3+i/10, b) 3-i/10, c) 3+i/8, d)3-i/8

Answer 4

:)

Answer 5

So I'm half right, and half in the obliquesphere...or you put the wrong eq up there...

Answer 6

- all terms are inside sqrt ?

Answer 7

Thats what I'm wondering... is it the 4 thats neg, or the sqrt of 4?

Answer 8

and is it just the four under sqrt, or all of it?

Answer 9

denominator is 5+2i or this all without -4 ?

Answer 10

it's √-4. So I know that it's impossible to find the square root of a negative # that's why it turns into an imaginary number. It would be i√4. Then you find the prime factors of 4 which are 2&2. Group the pair. So it turns into 2i. I just don't know how to do the rest and get the correct answer.

Answer 11

It's √-4 over (5+2i)-(3+4i)

Answer 12

3+(i/10)

Answer 13

so but inside sqrt is just 4 or the denominator too ?

Answer 14

2i i
------ = ------
2-2i 1-i

Answer 15

√-4/(5+2i)-(3+4i)
(2i)/(3-2i)
3+i/8 (oh sorry lol)

Answer 16

how do you like this ?

Answer 17

/facepalm
I hated that question.

Answer 18

"Please sir, may I have another?"

Answer 19

(in another thread)

Answer 20

denominator is (5+2i) -(3+4i) ?

Answer 21

Dyiliq check it please 5-3 is not equal 3

Answer 22

√-4/(5+2i)-(3+4i)
(2i)/(2-2i)
3+i/8
woops

Answer 23

why ?

2i i
------- = -------
2(1+i) 1+i

Answer 24

sorry i/(1-i)

Answer 25

i(1+i)/(1-(-1)) = (i - 1)/2

Answer 26

invert

3+i/8 = i/2
(2i)/(3-2i) = i/2
√-4/(5+2i)-(3+4i) = i/2

Answer 27

sorry again lolz (2i)/('2'-2i)

Answer 28

and 3+i/8= (-i)/(2)

Answer 29

(2i)/(2-2i) = (-i)/2
√-4/(5+2i)-(3+4i) = (-i)/2