Question

8^(y-2) =2y

Answer 1

take log to both sides :)

Answer 2

yeah thats it by taking log we will have
(y-2)log8=log2+logy
is it right ??? @Eyad

Answer 3

y= -1?

Answer 4

yes @annas thats right :)

Answer 5

is it maybe
\[8^{y-2} =2^y\]??

Answer 6

okey dokey @Eyad

Answer 7

xD @annas.

Answer 8

yea satellite thats the equation

Answer 9

that would make life a lot easier. if it is
\[8^{y-2}=2^y\] then since \(8=2^3\) you get
\[2^{3y-6}=2^y\]making
\[3y-6=y\] and then you can solve for y easily

Answer 10

2power y???
@tmest1992

Answer 11

you get
\[3y-6=y\]
\[2y=6\]
\[y=3\]

Answer 12

gimmick is to write both sides with the same base

Answer 13

no the only power is (y-2)

Answer 14

ok if there is no power on 2 then it will be done by log method