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Mathematics 9 Online
OpenStudy (anonymous):

http://img204.imageshack.us/img204/8272/f72fd82249d44e6b84cc138.png Can anyone explain how you would get that answer for this limit?

OpenStudy (anonymous):

well, the -1/216 comes from the right term ; 6^(x-1)/6(x+2) = 6^(x-1-(x+2)) = 6^-3, but I'm not sure how to get rid of the left part

OpenStudy (turingtest):

\[{4^{x+1}-6^{x-1}\over{6^{x+2}}}={2^{2x+2}\over(2\cdot3)^{x+2}}-6^{-3}={2^x\over3^{x+2}}-6^{-3}\]since the denominator on the left will grow faster than the numerator, the first term goes to zero in the limit and we are left with \(-6^{-3}\)

OpenStudy (anonymous):

Oooh I see thanks!

OpenStudy (turingtest):

welcome :)

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