Given: ΔABC ≅ ΔEDF

What is the length of FE rounded to the nearest tenth?

3

4

1.1

3.2

Question

Given: ΔABC ≅ ΔEDF
 
What is the length of FE rounded to the nearest tenth?

 3

 4

 1.1

 3.2

sarahc · Answer

attachment

campbell_st · Answer

you need pythagoras' theorem the find the side lengths in triangle ABC

BC = 3 AB = 1 and $$AC = \sqrt{10}$$

FE is the same length as AC since corresponding sides in congruent triangles are equal

 $$FE = \sqrt{10}$$

campbell_st · Answer

you'll need to evaluate FE to 1 decimal place

phi · Answer

ΔABC ≅ ΔEDF
that means the two triangles are the same size and shape.  So side FE is the same length as AC

phi · Answer

Do you know how to find the distance between 2 points?

sarahc · Answer

Thank you ! I understand. Phi- the distance formula

phi · Answer

You get Campbell's answer sqrt(10)

sarahc · Answer

Yes 3.16 . thanks! :)

phi · Answer

careful!  nearest tenth.  so you must round 3.16  to 3.2