if a plane can travel 490 mph with the wind and 430mph against the wind, find the speed of the plane in still air
hello deano8677 :) make a diagram first.
i made one and it doesnt seem to be helping me :(
use algebra! :DDD upstream speed = speed of plane (still) - speed of current downstream speed = speed of plane (still) + speed of current need more hints? or are you good? :D
(490+430)/2=460mph
well ya i kinda do need more hints lol
that was more confusing to me than the ?
let x = speed of plane (still) and c = current downstream speed = 490 mph = x + c upstream = 430 = x - c x + c = 490 x - c = 430 what about now? getting it? :DDD
so it would be 460?
hmmm remember you're looking for speed of plane (still) which is x...you use systems to cancel the speed of current (which is c) so you add the system to cancel c
so my formula is x-c(X) + c=490
wait..what did you do? x + c = 490 x - c = 430 add the 2 equations (x+x) + (c - c) = (490 +430) 2x + 0 = 920 getting it now?
im sorry my computer froze on me
so wouldnt that make it 460?
2x=920 x=460
right! :D
LOL i said that 20 minutes ago!!! thanks for all your help though!!!!!! greatly appreciated
that was one of those its so easy its hard ?s
ohhh...well the time thing of openstudy is buggy lol....deceived me haha wish they could fix it @_@ anyway glad to have helpedyou understand..it just takes experience haha
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