Question

Find h'(2), given that f(2)=-3, g(2)=4, f'(2)=-2, and g'(2)=7.

g(x)/(1+f(x))

now, I know how to do it without the "1" but I never did it with anything else than the basic g(x)/f(x).

Answer 1

you know the quotient rule?

Answer 2

..or product rule + chain rule gives the same results

Answer 3

ya, i know them

Answer 4

let\[u=g(x)\]and\[v=1+f(x)\]now find the derivative of \[u/v\]

Answer 5

but the formula only tells you what to do with the f(x) and the g(x) where does the "1" go?

Answer 6

wait, what?

Answer 7

what is the derivative of any constant?

Answer 8

0

Answer 9

so that's where the 1 goes
poof!

Answer 10

ahhh

Answer 11

i wasn't thinking about that

Answer 12

let me know if you still get tripped up

Answer 13

ok, thanks for the help, I should have it