Find h'(2), given that f(2)=-3, g(2)=4, f'(2)=-2, and g'(2)=7.

g(x)/(1+f(x))

now, I know how to do it without the "1" but I never did it with anything else than the basic g(x)/f(x).

Question

Find h'(2), given that f(2)=-3, g(2)=4, f'(2)=-2, and g'(2)=7.

g(x)/(1+f(x))

now, I know how to do it without the "1" but I never did it with anything else than the basic g(x)/f(x).

turingtest · Answer

you know the quotient rule?

turingtest · Answer

..or product rule + chain rule gives the same results

anonymous · Answer

ya, i know them

turingtest · Answer

let$$u=g(x)$$and$$v=1+f(x)$$now find the derivative of $$u/v$$

anonymous · Answer

but the formula only tells you what to do with the f(x) and the g(x) where does the "1" go?

anonymous · Answer

wait, what?

turingtest · Answer

what is the derivative of any constant?

anonymous · Answer

attachment

turingtest · Answer

so that's where the 1 goes
poof!

anonymous · Answer

ahhh

anonymous · Answer

i wasn't thinking about that

turingtest · Answer

let me know if you still get tripped up

anonymous · Answer

ok, thanks for the help, I should have it