Question

Find the sum of the measures of the interior angles of each convex polygon.

Answer 1

overall

Answer 2

Here is the question: 16-gon

Answer 3

???

Answer 4

i dont know

Answer 5

It wants me to find the sum of a convex polygon and the polygon is a 16-gon

Answer 6

& I can't seem to figure it out.

Answer 7

Use the formula (n-2)*180

Answer 8

Ok, So would it be 16 in place of the n?

Answer 9

You will get 2520 degrees

Answer 10

Ok, But what number would I put in place of the n?

Answer 11

16

Answer 12

Alright thanks man, Can ya help me with a couple of more?

Answer 13

ok

Answer 14

My next one is: The measure of the interior angles of a regular polygon is given. Find the number of sides in the polygon.

Answer 15

Here is the question: 1980.

Answer 16

Sum of the angles is 1980?

Answer 17

I just got to find the polygon that has a number of sides of 1980.

Answer 18

Thats basically what it is.

Answer 19

..Sam, Can ya help?

Answer 20

\[\frac{(n-2)\times180}{n}=\text{Each \angle inside the polygon}\]
\[(n-2)\times180=\text{Sum of angles inside the polygon}\]
----------------------------------------------------------
So,
\[(n-2)\times180=\text{Sum of angles inside the polygon}\]
\[(n-2)\times180=1980\]
n=13

Answer 21

Alright thanks, Can ya help with 4 more lol? Sorry man

Answer 22

post as a new question

Answer 23

Alright, Give me a min

Answer 24

The equation is (180)(n-2), where n is the number of sides. Here's why:


The number of triangles that I can split the polygon up into, is n-2. Each triangle's interior angles sum to 180. How cool! =D