tan θ sin θ + sin θ = 0 Solve the given equation.
First step is to factor the left side.
Can you do that?
I'm not really sure how. This is the first type of this particular problem on my homework assignment.
How would you factor ax+x?
Factor out the X
Sin Theta(Tan Theta + 1) ?
right
Do you know what's next?
Try to get it as a single trig identity? I'm not sure...
you have a product of two things: sin(theta) and tan(theta + 1) and that product equals 0, so at least one factor is 0.
So sin(theta)=0 or tan(theta)+1=0 Similar to how you would solve (x+1)(x+2)=0 -> x+1=0 or x+2=0 for example.
So I just find where they equal 0?
Sin theta = 0 at 2pi and pi, and tan theta = -1 at 7pi/4 ad 5pi/4
And then I just add on 2pi K and pi K for where Sin theta = 0 and where Tan theta = -1?
I think..
you're right about the sine part, but tan(5pi/4)=1
oooo 3pi/4, got the circle mixed up
So would the solution be 2pi+2pi k, pi + 2pi K, 7pi/4 + pi k, and 3pi/4 +pi k?
yes, you can simplify that though.
Alright I got the question right
Thanks a lot!
I feel compelled to write down the simplified answer: x=k pi or x= k pi -1/4 pi
Gotcha, My professor allows us to leave our answers unsimplified. Thanks again.
ok then, you're welcome.
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