hod would i write the domain and range for f(x) = (√3-x) + 2
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OpenStudy (anonymous):
Let's do the domain first: you can't take the square root of a negative number, so 3-x>=0
OpenStudy (anonymous):
So...?
OpenStudy (anonymous):
@thomas9 sorry late reply. domain: {x ≤3 }
OpenStudy (anonymous):
right,so thats the domain.
for the range: the square root is >=0, so all values of f>=?
OpenStudy (anonymous):
f ≥ 2
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OpenStudy (anonymous):
right so the range is everything>=2
OpenStudy (anonymous):
how come when we're looking for the range we don't include the + 2 part? :S
OpenStudy (anonymous):
you mean the domain?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
the domain is the set of all values of x that you can put into the function. So you look for roots or logarithms or places where you might divide by zero. the +2 doesnt affect the values you can put in.
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OpenStudy (anonymous):
so say i was given the equation p(x) = (√x^2 - 5)
the domain would be x ≤ -√5 ?
OpenStudy (anonymous):
√(x^2 -5)?
OpenStudy (anonymous):
i mean yeah
OpenStudy (anonymous):
it'd be x>=√5 or x<=-√5
but i believe you get the point, right?
OpenStudy (anonymous):
oh okay :) and yeah i get it. thanks!
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