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Mathematics 11 Online
OpenStudy (anonymous):

hod would i write the domain and range for f(x) = (√3-x) + 2

OpenStudy (anonymous):

Let's do the domain first: you can't take the square root of a negative number, so 3-x>=0

OpenStudy (anonymous):

So...?

OpenStudy (anonymous):

@thomas9 sorry late reply. domain: {x ≤3 }

OpenStudy (anonymous):

right,so thats the domain. for the range: the square root is >=0, so all values of f>=?

OpenStudy (anonymous):

f ≥ 2

OpenStudy (anonymous):

right so the range is everything>=2

OpenStudy (anonymous):

how come when we're looking for the range we don't include the + 2 part? :S

OpenStudy (anonymous):

you mean the domain?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

the domain is the set of all values of x that you can put into the function. So you look for roots or logarithms or places where you might divide by zero. the +2 doesnt affect the values you can put in.

OpenStudy (anonymous):

so say i was given the equation p(x) = (√x^2 - 5) the domain would be x ≤ -√5 ?

OpenStudy (anonymous):

√(x^2 -5)?

OpenStudy (anonymous):

i mean yeah

OpenStudy (anonymous):

it'd be x>=√5 or x<=-√5 but i believe you get the point, right?

OpenStudy (anonymous):

oh okay :) and yeah i get it. thanks!

OpenStudy (anonymous):

cool, you're welcome.

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