Question

Solve the following system of equations.
2a – 3b + c = 10
2a – 2b – 2c = 2
a + 3b + 2c = –1

Answer 1

we can do this using a matrix, if you are familar with that

Answer 2

Gauss-Jordan process

Answer 3

correct

Answer 4

I'm still trying to figure out how to do it using matrices

Answer 5

The method intrigues me. No, I take that back...It defeats me.

Answer 6

its the same as elimination Hero.... just without the pronumerals

Answer 7

rref{{2,–3,1,10},{2,–2,–2,2},{1,3,2,–1}}

then read off the right column for answers

Answer 8

http://www.wolframalpha.com/input/?i=rref%7B%7B2%2C%E2%80%933%2C1%2C10%7D%2C%7B2%2C%E2%80%932%2C%E2%80%932%2C2%7D%2C%7B1%2C3%2C2%2C%E2%80%931%7D%7D

Answer 9

I guess

Answer 10

the row reduce algorithm is just the elimination method

Answer 11

Yeah, but why do we need to multiply by fractions and such to row reduce. . Seems weird to me. And then the final result has to be 1's and 0's. What's up with that?

Answer 12

each column represents one of the variables; so in order to have the solution to 1 variable; the rest of the entries in that column have to be eliminated

Answer 13

add a multiple of one row to another in order to eliminate the variable in that row ....

Answer 14

the idea is to get 1 as the coeffiecient of each pronumeral

Answer 15

So the 1's represent the variable solved for a value. The first row means that a = 1
second row means b = -2. Third row means c = 2

@amistre64

Answer 16

yep

Answer 17

Okay, that's all I need to know. Thanks.

Answer 18

Hi