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Mathematics 7 Online
OpenStudy (anonymous):

in a camp the food supply for 200 men could last for 20 days. if 300 more men arrived in the camp, how long will the food supply last? how do you solve this?

OpenStudy (anonymous):

i don't think that is what the question is asking. not if there are 300 total, but rather if 300 more are added

hero (hero):

Keno, you shouldn't invade someone else's question by posting your own.

OpenStudy (anonymous):

hero your answer cannot be possible

OpenStudy (anonymous):

If you don't understand Hero's approach to the problem let us know. I have a different approach.

OpenStudy (anonymous):

what is your approach romero

hero (hero):

@sasdell02234 , it's possible

hero (hero):

What makes you think that it isn't possible?

hero (hero):

Actually, I think you might have a point

OpenStudy (anonymous):

@Hero the answer to that proportion is 30. how could the number of days increase if the amount of men has increased, therefore causing the amount of food to decrease faster hence being a number of days less than 20.

OpenStudy (anonymous):

excuse me, the answer to your proportion was 50

hero (hero):

I'm working on it. I see that we have the wrong set up here.

OpenStudy (anonymous):

indeed

OpenStudy (anonymous):

do it with numbers each mean eats one hamberger a day. there are 200 mean and 20 days so there are \(200\times 20=4000\) hambergers. now there are 500 mean and 4000 hamburgers. each man eats one hamburger a day, then there are \(4000\div500=8\) day supply

OpenStudy (anonymous):

@satellite73 That is also what I go. Doesnt make sense that the days will increase if more people come.

OpenStudy (anonymous):

mean, men, whatever

OpenStudy (anonymous):

@satellite73 you've done it again. Thank you :)

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

\[({200\over20}÷{500\over20})20=8days\]

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