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Mathematics 16 Online
OpenStudy (anonymous):

See attachment

OpenStudy (anonymous):

number 7-9 I don't understand how to find the lateral of a cone.

OpenStudy (anonymous):

You aren't able to view it? @Directrix

OpenStudy (anonymous):

LateralArea=(pi)(r)(g)

OpenStudy (campbell_st):

the surface area is the area of every face Question 4 base = 4 x 4 = 16 triangle = 1/2 x 4 x10 = 20 4 triangles Surface Area = 16 + 4 x 20 96 m^2

Directrix (directrix):

7. Lateral Area of Cone = pi * r * L where L is the slant height LA = pi * 5*10 LA = 50 pi = 157.08 square meters

Directrix (directrix):

8. LA = pi*r*L where L is slant height LA = pi * 6 * 10 LA = 60 pi = 188.50 square feet

Directrix (directrix):

Question time.

OpenStudy (anonymous):

Explain number 4! :D

Directrix (directrix):

This is the figure for #8.

Directrix (directrix):

@sakigirl --> I thought you wanted to do 7-9.

OpenStudy (anonymous):

I understand them

Directrix (directrix):

??? sakigirl number 7-9 I don't understand how to find the lateral of a cone.

OpenStudy (anonymous):

I understand it now. Isn't number 9: 304.52?

Directrix (directrix):

I haven't done number 9. I'm looking at #4 now. Do you know the formula for the lateral area of regular square base pyramid? Actually, we can just find the area of one triangular face and multiply by 4.

OpenStudy (anonymous):

Can we do both? Number 9 first, because it's just checking, and then number 4

Directrix (directrix):

Okay, you do number 4 while I do number 9.

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

I have 4

Directrix (directrix):

9. LA = pi*r*L where L is the slant height LA = pi*6*sqrt(261) LA = 304.52 square centimeters

Directrix (directrix):

What did you get for #4?

OpenStudy (anonymous):

189

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

I have 140. LA = 4 * (1/2) * 7 * 10

Directrix (directrix):

If a pyramid is regular the 4 lateral faces are congruent and have the same area.

OpenStudy (anonymous):

My teacher taught us the formula B+(1/2)Pl

OpenStudy (anonymous):

Oh it's asking to find the surface area, not the lateral :P

Directrix (directrix):

If you take the 4 triangles 1/2 *7*10 + 1/2*7*10 +1/2 *7*10 + 1/2*7*10 = [(1/2)*10](7 + 7 + 7 + 7) --> factoring out the [ (1/2)*10], you get (1/2) L times perimeter of the base. Total Area = Lateral Area and area of Base = 140 + 49 = 189 square meters

OpenStudy (anonymous):

OpenStudy (anonymous):

This one also

Directrix (directrix):

What did you get for slant height?

OpenStudy (anonymous):

See, I don't know. I can't find it

Directrix (directrix):

Directrix (directrix):

Solve for L.

Directrix (directrix):

Let me know what you get.

OpenStudy (anonymous):

611.7556

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

yes, that's what I got. and, then 924981.12 for the lateral area. Yes?

OpenStudy (anonymous):

yes

Directrix (directrix):

And, total area is ?

OpenStudy (anonymous):

572315.22

Directrix (directrix):

That is just the base area, I think.

OpenStudy (anonymous):

I don't know then. I keep getting that answer

Directrix (directrix):

Well, maybe not. Lateral area = 924981.12 Base area = 571536 Total area = 1 496517.1

OpenStudy (anonymous):

Didn't you say that the lateral was 611.76?

Directrix (directrix):

924981.12 for the lateral area. Yes? From above. You agreed to it.

Directrix (directrix):

lateral was 611.76? That was for once face of something, I have forgotten what.

Directrix (directrix):

When you say "lateral," I do not know if you are talking about lateral area of the solid or area of one lateral face. Try to be more specific.

Directrix (directrix):

My figures may be wrong but check yours against them.

OpenStudy (anonymous):

I'm so sorry, can you explain everything? @Directrix Tired and confused

Directrix (directrix):

Can we take the problem to a new thread. I'm getting one "running scripts, about to stop" error message after another.

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