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Chemistry 14 Online
OpenStudy (anonymous):

I need lots of help! Show all math performed (label the calculation or give the formula, show your setup, and give the result), include proper labels, and/or answer any questions listed below. Graph temperature vs. volume. Temperature should be on the horizontal axis and should number from -300 to 200 degrees C. (Use the long side of the graph paper for temperature) Volume should be on the vertical axis and should be numbered from 0 to 200ml. A sample graph is shown below. You will want to make a larger version of this graph on a full sheet of paper, including more detailed units on

OpenStudy (anonymous):

what calculations are you trying to do?

OpenStudy (anonymous):

idk...my brain is fried and I have to get this done. I just copied and pasted it umm hold on let me see if this will work

OpenStudy (anonymous):

OpenStudy (anonymous):

Alright so how far have you gotten in your experiment?

OpenStudy (anonymous):

um I've stared at it and begged the gods of OS for help. I got 2 hours of sleep last night and it's 115am my time. :(

OpenStudy (anonymous):

Well for the graph i would pick a gas, and use the ideal gass law in 100 degree's at a time from -300 to 200 and do a best fit line to get a general model of how tempature effects volume.

OpenStudy (anonymous):

best fit line? thanks btw!

OpenStudy (anonymous):

yea just make a straight line that generaly reflects what the data is showing. Do you know how to use the ideal gas law?

OpenStudy (anonymous):

eeehhh kinda sorta not really

OpenStudy (anonymous):

\[PV=nRT \] but we want to keep everything the same and solve for v so we are going to rearange that to \[V=\frac{nRT}{P}\]

OpenStudy (anonymous):

How do you remember all this?!

OpenStudy (anonymous):

I don't always I have to look things up sometimes, I can't remeber what the value for R is right now but it's a constant but other than that i would keep everything else 1 just to make it easy.

OpenStudy (anonymous):

R=8.314 J/mol K

OpenStudy (anonymous):

Don't forget you have to change your degrees C to Kalvin

OpenStudy (anonymous):

okay! thanks so much!

OpenStudy (anonymous):

No problem best of luck to you and if you get in a jam I might be around a little longer but this should be enough for you to get a start on it.

OpenStudy (anonymous):

okay! thanks. If you don't mind I might just msg you if I need help?

OpenStudy (anonymous):

Sounds Good

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

just draw an increasing diagonal line and then put V/T = constant somewhere on ur graph and ul get full credit lol

OpenStudy (anonymous):

hahahah @FlyersMania14 I wish lols

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