DETERMINE 2 PAIRS OF POLAR COORDINATES FOR THE POINT (((-3RAD3)/2),(3/2)) WITH O<=THETA<=2PI
Is this point given in Cartesian and you want to convert it to polar?
no just a normal coordinate plane
That's what Cartesian is, the x-y plane. I need to know if x = (-3RAD3)/2) and y = 3/2
ye
i figured out an answer but it is conflicting with other people's
???? u there?
I was working with another person when you pinged me or whatever. I'm here now.
Who are these other people? Maybe they are correct.
idk
they gave me the answers (3, -60) (3,300) which is what i got but the right answer in the book is (3, 120) (2,-240)
You did not specify degrees so I chose radians.
thats fine but can u elaborate on what u jusst said
The point is in the second quadrant with theta = 120 and r = 3/2. ( 3/2, 120) in polar form. How about ( -3/2, -60) and (3/2, 120) for one pair. For another, (3/2, 480) and (-3/2, -60)
Did you check these points? I'd like to know what the others got because there are infinitely many possibilities.
well they gave me -60 and 300 for the angles but i still dont get how u can get 120
(3, 120) (2,-240) ==> the r values cannot be different.
but aren't they different 3 and 2
or is that typo?
Look at this restriction we ignored --> WITH O<=THETA<=2PI
I think you typo-ed.
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