Use cylindrical coordinates to set up the integral of f(x, y, z) over the region outside the cone z^2=x^2+y^2 and inside x^2+y^2+z^2=9. Please don't solve it for me, I'm just having trouble finding the limits of integration.
Use the conversion equations from Cartesian to cylindrical and find out where the cone and the sphere intersect. :D
Um... they intersect at x^2+y^2=9-x^2-y^2. So r=3/rad(2). Still confused. This is one of the first problems I've done of this type. Still confused on the limits.
I'd divide the region into two parts but it would be ugly. :(
Help would still be appreciated.
\[ \int _0^{\frac{3}{\sqrt{2}}}\int _r^{\sqrt{9-r^2}}rdzdr = 9-\frac{9}{\sqrt{2}} \]
Aren't you lacking a d(theta)?
Multiply by 2 pi the above answer.
Oh yeah, My bad. =))
\[ \int_0^{2 \pi} \int _0^{\frac{3}{\sqrt{2}}}\int _r^{\sqrt{9-r^2}}rdzdrd\theta = 2\pi \left(9-\frac{9}{\sqrt{2}}\right) \]
You can practice similar problems and more on http://moltest.missouri.edu/mucgi-bin/calculus.cgi Chose CalcIII (Multiple Integrals)
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