Question

Lgbariddle >:))

Using any Maths Symbols or Signs prove it...

0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

You can Insert Everything but Numbers,
And you can't change everything.

Answer 1

Can I insert any amount of symbols?

Answer 2

Lgbariddle- nice name.

Answer 3

It's easy for 5: 5+5/5=6, but I have no idea how to make 6 out of 0's. =))

Answer 4

I will do a few:

(1+1+1)! = 6

Answer 5

yes..as long as you dont put new numbers in

Answer 6

1 down :D

Answer 7

(0+0+0)!=6
(1+1+1)!=6
2+2+2=6
3*3 -3 = 6
sqrt4 + sqrt4 +sqrt4 = 6

next batch coming up

Answer 8

That's works for (0!+0!+0!)!=6

Answer 9

oops 0 i did wrong

Answer 10

LOL o.O

Answer 11

\[0+0+0+\frac{x+x+x+x+x+x}{x}=6\]lolol

Answer 12

Hey, nobody accused me of being clever. :D

Answer 13

hmmm 0-4 down

Answer 14

lol @badreferences =)))

Answer 15

\[ (\cos (0) + \cos (0) + \cos (0) )!= 6 \]

Answer 16

^that's actually the real one for 0 hehe

Answer 17

well, 0! method works as well.

Answer 18

guess so haha

Answer 19

\[\left(\lim_{x\to\infty}\frac{9+9+9}{x}\right)+\frac{x+x+x+x+x+x}{x}\]lololol

Answer 20

lol no x's :PPP

Answer 21

6+6-6 =6

Answer 22

7-7/7=6

Answer 23

Okay I will do from the behind,

\[ (\sqrt9 \times \sqrt9 ) – \sqrt9 = 6 \]

Answer 24

6 and 7 down

Answer 25

8 left

Answer 26

oh 5 too

Answer 27

Sum of the cube roots of three 8 is 6.

Answer 28

i dont thing using a cube root would be allowed, would it?

Answer 29

wow lgba

Answer 30

oh well, ffm did it, so must be

Answer 31

izallowed @apoorvk so 8 down

Answer 32

5 is easy =))

Answer 33

\sqrt{9}-\sqrt{9}+\sqrt{9}!

Answer 34

Like seven.

Answer 35

lol that's 2 :P hahahah

Answer 36

6+6-6 = 0

Answer 37

\[\sqrt9-\sqrt9+\sqrt9!=3!=6\]

Answer 38

6+6-6 is 6 not zero lol

Answer 39

so are we done?

Answer 40

No, I'm lobbying that my previous answers are the best.

Answer 41

yeah =)) but 5 is 5 + 5/5 not 5/5 + 1 lol

Answer 42

lol i meant 6

Answer 43

sqrt9 * sqrt9 - sqrt9

Answer 44

In particular \[\left(\lim_{x\to\infty}\frac{9+9+9}{x}\right)+\frac{x+x+x+x+x+x}{x}\]

Answer 45

it is finished

Answer 46

Oh yes typo :P

Answer 47

3! +3-3= 6

Answer 48

lol badrefs with the x's hahaha

Answer 49

oh, nine's done :/

Answer 50

Good one, LGBA

Answer 51

<tips hat>

Answer 52

wait is my 3 one right?

Answer 53

could be....hehe =))

Answer 54

yeah!