Car A leaves Sydney for Brisbane at 8:00 am and traveled at an average speed of 60km/h. At 9:00am Car B also leaves Sydney for Brisbane. If Car B at an average speed of 80km/h, at what time will it overtake Car A?

Question

lgbasallote · Answer

you do know you couldve just edited the question a while ago there and then right....anyway....

anonymous · Answer

No I didn't know that

lgbasallote · Answer

it's the link beside Report Abuse i thin..

lgbasallote · Answer

anyway...

at 9:00
Car A = 60 km
Car B = 0km

10:00 
Car A = 120 km
Car B = 80 km

11: 00
Car A = 180
Car B = 160
(getting near)

12:00
Car A = 240
Car B = 240

:O lookie! we have an overtaker yay!!! so...12:00 is how many hours from 9:00?

lgbasallote · Answer

uhhh @Genuine might wanna give some feedback there /:)

anonymous · Answer

@lgbasallote  is right

anonymous · Answer

@lgbasallote  Oh thanks! (:

anonymous · Answer

But is there like a way to solve this question with an equation?

lgbasallote · Answer

oh yeah...im thinking it out wait...

lgbasallote · Answer

i think i got it...

let t = Car B's time thing
(t+1) = Car A's time (because it starts 1 hr before Car B)

d_A = d_B <---overtake

60(t+1) = 80(t)
60t + 60 = 80t
60 = 80t - 60t
60 = 20t
3 = t

seems about right :DDD

anonymous · Answer

Why do people think I am you?

anonymous · Answer

@lgbasallote I never thought of that method (:
But the example in my book says something about 
(t + 3/2) or something, would you know what it means?

lgbasallote · Answer

hmmm is it regarding this same problem? will you post the whole solution? maybe i can figure it out then

anonymous · Answer

No it's not the exact same question but it's very similar:
Car A left Sydney for Melbourne at 6am and traveled at an average speed of 80km/h. At 7:30 am car B left Sydney for Melbourne. If car B travels at an average speed of 100km.h, at what time will it catch car A?

lgbasallote · Answer

ahhh that's where 3/2 came from...7:30 is 1 1/2 hrs from 6:00 aka 3/2 hrs

anonymous · Answer

And the solution for it is:
Car B will catch A when both have traveled the same distance. Now D=ST and let time be T be the time that car B catches up with car A. For car A it travels for 
(T+3/2)hours and for a distance of 80(T+3/2)
For car B it travels for T hours and for a distance of 100T.
Thus the distance traveled by both cars is the same...

lgbasallote · Answer

....i already said where 3/2 came from @Genuine :P

anonymous · Answer

Oh yeah, thank you again for your help (:

lgbasallote · Answer