this is a math question:PERCENTAGE
the kinetic energy of a body increses by 300% then the new momentum of the body increases by how much percent?
u only need to know these terms
k.e=1/2*m*v^2
momentum=m*v
where k.e is kinetic energy
v is velocity
m is mass
*****mass remains constant

Question

this is a math question:PERCENTAGE
the kinetic energy of a body increses by 300% then the new momentum of the body increases by how much percent?
u only need to know these terms 
k.e=1/2*m*v^2
momentum=m*v
where k.e is kinetic energy
v is velocity
m is mass
*****mass remains constant

apoorvk · Answer

okay so mass is constant.
so basically the "v^2" quantity increases by 300%, that is
 (v')^2 = 4v^2

so, v' = 2v

Now since "v" gets doubled. momentum "mv" also gets doubled.

so, momentum increase by 100%.

apoorvk · Answer

here (v') is the new velocity.

anonymous · Answer

can u expalin why the second step?

apoorvk · Answer

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