Question

f(x)=x(t)=t(p)=p(y)=y(f).
what is df/dp ?

Answer 1

1.

The key is to use the fact that the derivatives must be the same.

\[df/dx=dx/dt=dt/dp=...\]

Then use the chain rule to show that \[df/dp=(df/dx)^3\] and \[df/dp=(df/dx)^{-2}.\]

The only way these can both be true is if \[df/dp=1.\]

Answer 2

That sound like CMAT to me, so I'm going to say that \[f(x(t(p)))\] is the general case that you want, so \[df/dp = df/dx \times dx/dt \times dt/dp\]

is all you need! I think so!

Answer 3

actually it is a equation like x=x.
which always has slope 1