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OpenStudy (anonymous):
What is the simplified form of the quantity ysquared minus 6y plus 8 over the quantity ysquared minus 7y plus 12 ? HELP
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OpenStudy (anonymous):
\[(y^2 - 6y + 8)/(y^2 -7y + 12)\] ?
OpenStudy (anonymous):
I mean is that what you're asking?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
(y-2)(y-4) / (y-3)(y-4)
OpenStudy (anonymous):
Numerator: -two numbers that multiply to 8 and add to -6: -4, -2 Therefore, (y^2 - 6y + 8) = (y - 4)(y - 2) Denominator: -two numbers that multiply to 12 and add to -7: -4, -3 Therefore, (y^2 - 7y + 12) = (y - 4)(y - 3) So the new fraction is: \[[(y - 4)(y - 2)]/ [(y - 4)(y - 3)]\] Then because it is all multiplication and division you can cancel the (y - 4)s: \[(y - 2)/(y - 3)\]
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OpenStudy (anonymous):
the (y-4) cancel and you're left with (y-2)/(y-3)
OpenStudy (anonymous):
THANKS GUYS :)
OpenStudy (anonymous):
you're welcome. makes sense?
OpenStudy (anonymous):
yup
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