Question

What is the simplified form of the quantity ysquared minus 6y plus 8 over the quantity ysquared minus 7y plus 12 ? HELP

Answer 1

\[(y^2 - 6y + 8)/(y^2 -7y + 12)\] ?

Answer 2

I mean is that what you're asking?

Answer 3

yes

Answer 4

(y-2)(y-4) / (y-3)(y-4)

Answer 5

Numerator:
-two numbers that multiply to 8 and add to -6: -4, -2
Therefore, (y^2 - 6y + 8) = (y - 4)(y - 2)

Denominator:
-two numbers that multiply to 12 and add to -7: -4, -3
Therefore, (y^2 - 7y + 12) = (y - 4)(y - 3)

So the new fraction is:
\[[(y - 4)(y - 2)]/ [(y - 4)(y - 3)]\]

Then because it is all multiplication and division you can cancel the (y - 4)s:
\[(y - 2)/(y - 3)\]

Answer 6

the (y-4) cancel and you're left with (y-2)/(y-3)

Answer 7

THANKS GUYS :)

Answer 8

you're welcome. makes sense?

Answer 9

yup