Question

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X.

Answer 1

What is the measure of angle ACB?

Answer 2

m∠angle = 1/2 |m - m| could be the formula! so i was thnking of multiplying 32 the angle by 2... and then subtract..but idkk.

Answer 3

Ahh I was gonna try to help you but I'm not that good at geometry. :( sorry

Answer 4

awhhh... :( thanks for trying..... hopefully someone else will try and help..

Answer 5

ask Fool For Math she's good at this stuff :)

Answer 6

*he he* @rebeccaskell94

Answer 7

okay! i am but i don't think she wants too... cuz i tried through chat..

Answer 8

what apoor lols

Answer 9

Is this solved yet?

Answer 10

@rebeccaskell94: How do you get the impression that I am a girl? :P

Answer 11

idk. I think someone told me that. are you a he?

Answer 12

I think you're onto something with the 32 * 2. That's going to be the measure of your arc XA. Then, lemme refresh my geometric theorems before continuing

Answer 13

what is \(153^\circ\) here?

Answer 14

okay whats 156 degrees in the diagram? Its a bit unclear.

Answer 15

then, if I'm not mistaken, I think that your angle C is going to be (156 - 64) /2 (that's pure instinct tho. Couldn't find the theorem to prove it yet)

Answer 16

156 seems to be the measure of the arc BA

Answer 17

the 156 is arc

Answer 18

Charron! i think your right..... that seems correct..! and 46 is one of my choices!

Answer 19

There is a wel known property:\[m\angle ACB = \frac 12 [m(arc \; AB) - m(arc( \;AX)) \]

Answer 20

and this is exactly what @m_charron2 used.

Answer 21

great! That's probably some sort of repressed memory that resurfaced...

Answer 22

so M32=1/2 {156-?) ??

Answer 23

You also need to know, the measure of an inscribed angle is half the measure of its intercepted arc.

Answer 24

so basically the answer is 46 right?? and yeah i remember that part but i didn't know we needed to 156-64... so yeah!

Answer 25

btw who should i give the medal too! you both helped a bunch!

Answer 26

Okay medal time :P and @rebeccaskell94: I am guy ;)

Answer 27

IDK who to give it 2... ill give it to you fool formath cuz you showed a formula! & can you guys help me with my next question??

Answer 28

Lol, thanks and I gave my medal to @m_charron2 he did solved it first. Lucky guess, memory surfacing are only modest conclusions :)

Answer 29

Okay dokey! :) thanksss uu

Answer 30

@Blahh23: Post it as a new thread.

Answer 31

I will. i don't think i need your help... if i come across another question i will deff let you know!! THANKS AGAIN!!! :))