Find the smaller solution for 3/5x^2−7=21 .
Is this the question?: 3/(5x^2) -7 = 21
no , 3over5xto the second power minus 7 equals 21
so like: 3/(5x^2 - 7) = 21 ?
yeah i guess
are you sure? It is important.
yeah its like that
So first I would multiply both sides by (5x^2 - 7): 3 = 21(5x^2 - 7) then expand the left side: 3 = 105x^2 - 147 then add 147 to each side: 150 = 105x^2 then divide both sides by 105: 150/105 = x^2 Is that as far as they want you to go with it? Or did I still misunderstand the question?
EDIT: expand the right side*
yeah , its not like that :/
is it like \[3/5 x^2 - 7 = 21\] ?
yes !!!!!! :) lol
ok so add 7 to each side: (3/5)x^2 = 21 - 7 (3/5)x^2 = 14 divide both sides by (3/5): x^2 = 14/(3/5) x^2 = 14 * (5/3) x^2 = 70/3 Hows that?
what 70/3 what does that mean ?
/ means division when you divide 70 by 3 you get 23.33....
Then you find the squar root ?
are you solving for x? if you are then you take the square root of both sides: x =about 4.83 (it can also be -4.83 but I don't know if you're expected to know that)
yes thats the answer thank you
no problem. do you understand how i found it?
yea i got it
great
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