AB = 4, BC = 17, CA =

Question

lgbasallote · Answer

AC = AB + BC try :D

mathteacher1729 · Answer

Something tells me there is more to this story...

lgbasallote · Answer

CA is a negative of that btw...because it's backwards

callisto · Answer

Is there a diagram? It is a triangle?

mathteacher1729 · Answer

My spider senses tell me that the goal is to find reasonable values for the third length of a triangle with verticies A,B, and C.

callisto · Answer

@mathteacher1729 Agree...

lgbasallote · Answer

or maybe we're just being paranoid and it's really that simple :P

anonymous · Answer

yes, mathteacher I think thats true

anonymous · Answer

What is it asking this person to do exactly?

lgbasallote · Answer

would be nice if he told us huh :))

callisto · Answer

@keno Can you tell us more about the question?

anonymous · Answer

A triangle has the following measurements. What is a possible length for the third side
AB = 4, BC = 17, CA =

lgbasallote · Answer

haha you guys were right :P

lgbasallote · Answer

|dw:1334711568237:dw|

$$CA = \sqrt{(17^{2} - 4^{2})}$$

callisto · Answer

Assume it is a right angle triangle. Use Pyth Thm to solve

Case 1, AC is the longest side
AB^2 + BC^2 = CA^2 
4^2 + 17^2 = CA^2
CA = sqrt (305)

Case 2,  BC is the longest side
AB^2 + CA^2 = BC^2 
4^2 + CA^2 = 17^2
CA = sqrt (273)