Question

cos2x+3sinx-2=0

Answer 1

\[\cos2x+3sinx-2=0 \]
OR
\[\cos^2x+3sinx-2=0 \] ?

Answer 2

first one

Answer 3

You have to make it like a quadratic equation,
Use the identity
\[\cos2x=1-2\sin^2x\]
----------------------------
From equation,
\[\cos2x+3sinx-2=0 \]
\[1-2sin^2x+3sinx-2=0 \]
\[-2sin^2x+3sinx-1=0 \]
Factor,
then you'll get
sinx=1, sinx=1/2

Answer 4

x=30,90,150

Answer 5

you can ask where you don't understand

Answer 6

so factoring I factor a sin out

Answer 7

yes
\[−2\sin^2x+3sinx−1=0\]

\[(−sinx+1)(2sinx−1)=0\]

Answer 8

ok got it.Im having so much difficulty understanding these identities. Thanks