Prove that A is in the subset B iff P(A) is in the subset P(B)
\[A \subseteq B\] iff \[P(A) \subseteq P(B)\]
\(P(A)\) is the power set of \(A\) correct?
Correct.
Since it's an iff statement, we need to prove implication in both directions. Let's start with \[A \subseteq B \Rightarrow P(A)\subseteq P(B)\]If we let some element \(a\in A\) that means that \(a\in B\) as well. The same is true for any subset of \(A\). So\[A' \subseteq A\Rightarrow A' \subseteq B\]Since the power set is defined as the set of all subsets, this means that \[A'\subseteq A \Rightarrow A' \subseteq P(A)\]and that\[A' \subseteq A\Rightarrow A' \subseteq P(B)\]This implies that \[P(A)\subseteq P(B)\] Now we still need to do the other way.
Suppose \(P(A)\subseteq P(B)\). Then we know that \(a\in P(A) \Rightarrow a\in P(B)\). However, since \(a\in P(A)\), this also implies that \(a\) is a subset of \(A\). Also, since \(a\in P(B)\) this implies that \(a\) is a subset of \(B\). Thus, it must be that \[A \subseteq B\]
You are awesome kingGeorge.
Why thank you. :)
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