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JP uses a paperweight shaped like a pyramid with a regular hexagon for a base. The side length of the regular hexagon is one inch. The altitude of the pyramid is 2 inches. What is the lateral surface area of this pyramid? Round your answers to the nearest hundredth.
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|dw:1334717734670:dw|
So, what have you done on this so far?
@sakigirl
I got 6
I think I'm going nowhere @Directrix
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Did you compute the slant height? That is going to be the major part of cranking out the answer.
The altitude comes down and intersects the hexagaonal base at its center. So , we will have to work on the floor of the pyramid to get one leg of a right triangle whose other leg is the height and whose hypotenuse is the slant height.
Agree? |dw:1334718767935:dw|
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