Question

cos (α- β) /sin α cos β =cot α + tan β

Answer 1

nice equation. what about it?

Answer 2

one side needs to equal the other side

Answer 3

are you trying to simplify it?

Answer 4

no proving that it is an identity

Answer 5

oh ok. I'll give it a shot

Answer 6

alright.

I used the right side to make the left. I'll use a as alpha and b as beta in my solution.

\[\cot(a) + \tan(b)\]
\[\cos(a)/\sin(a)\ + \sin(b)/\cos(b)\]
\[(\cos(a)\cos(b) + \sin(a)\sin(b) )/(\sin(a)\cos(b))\]
\[\cos(a-b)/(\sin(a)\cos(b))\]

Answer 7

expand \[\cos (\alpha-\beta)=\cos \alpha \cos \beta +\sin \alpha \sin \beta\]
divide each term on RHS by \[\sin \alpha \cos \beta\]. You'll have the answer

Answer 8

thank yall