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I can try to help
I just don't get it.
it's due at midnight. /:
alright you are going to want to start off with the one you know most about, which is the NaOH. Then use some stoicometry to figure out this bad boy, I will attempt to set it up for you
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\[45.3 ml NaOH(\frac{.111 mole NaOH}{1000 ml NaOH})=.00503 mole NaOH\]
alright now we no that this is a one to one change so we also have .00503 mole HClO4
\[\frac{.00503 mole}{.015L}=.335 M HClO_4\] try that one out see how it goes
oh okay thank-you.
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I'll submit in a few, I'll tell you.
ahh! thank you.
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