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Chemistry 7 Online
OpenStudy (anonymous):

Please help me?

OpenStudy (anonymous):

I can try to help

OpenStudy (anonymous):

OpenStudy (anonymous):

I just don't get it.

OpenStudy (anonymous):

it's due at midnight. /:

OpenStudy (anonymous):

alright you are going to want to start off with the one you know most about, which is the NaOH. Then use some stoicometry to figure out this bad boy, I will attempt to set it up for you

OpenStudy (anonymous):

\[45.3 ml NaOH(\frac{.111 mole NaOH}{1000 ml NaOH})=.00503 mole NaOH\]

OpenStudy (anonymous):

alright now we no that this is a one to one change so we also have .00503 mole HClO4

OpenStudy (anonymous):

\[\frac{.00503 mole}{.015L}=.335 M HClO_4\] try that one out see how it goes

OpenStudy (anonymous):

oh okay thank-you.

OpenStudy (anonymous):

Did it work?

OpenStudy (anonymous):

I'll submit in a few, I'll tell you.

OpenStudy (anonymous):

ahh! thank you.

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