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evaluate indefinite integral using the substitution method ....
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\[\int\limits_{}^{}e ^{2x-3}dx\]
if you want to be a wise guy you can start this as \[\frac{1}{e^3}\int e^{2x}dx\] and then use \(u=2x,du=2dx,\frac{1}{2}du=dx\) and integrate \[\frac{1}{2e^3}\int e^udu\]
Let u=2x-3 and du=2dx
ok thanks guys i got it from here i dont want the answer
thanks
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lol
Haha, that is very clever satellite.
just being silly it is late
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