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Mathematics 16 Online
OpenStudy (anonymous):

evaluate indefinite integral using the substitution method.........

OpenStudy (anonymous):

nice that they tell you what method to use!

OpenStudy (anonymous):

\[\int\limits_{}^{}e ^{2x ^{2}+1}xdx\]

OpenStudy (anonymous):

lol. let u=2x^2+1

OpenStudy (anonymous):

or be a wise guy and write as \[e\int e^{2x^2}xdx\]

OpenStudy (anonymous):

ignore me, do what sparkles says

OpenStudy (anonymous):

Sorry for typing lol... we all have to start somewhere :)

OpenStudy (anonymous):

\(u=2x^2+1, du=4xdx, \frac{1}{4}du=xdx\)

OpenStudy (anonymous):

\[\left( e ^{2x ^{2}+1} \right)/4 + K\] ??????

OpenStudy (anonymous):

um...no. integral e^u du where u=2x^2+! and du=4xdx

OpenStudy (anonymous):

ugh

OpenStudy (anonymous):

yes and you can check that it is right by differntiating

OpenStudy (lgbasallote):

why do i have a feeling this has an imaginary error function....o.O

OpenStudy (anonymous):

which is it right or wrong lol

OpenStudy (anonymous):

@myluv4u you have the right answer

OpenStudy (anonymous):

thank you yay!!!

myininaya (myininaya):

@igbasallote I think you missed the x multiplier like I did at first

OpenStudy (anonymous):

\[\frac{1}{4}e^{2x^2+1}+C\]

OpenStudy (lgbasallote):

oh yeah..don't mid me..do what satellite and sparkles are doing :p

OpenStudy (lgbasallote):

dont mind me*

OpenStudy (anonymous):

thanks all

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