Mathematics
16 Online
OpenStudy (anonymous):
evaluate indefinite integral using the substitution method.........
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
nice that they tell you what method to use!
OpenStudy (anonymous):
\[\int\limits_{}^{}e ^{2x ^{2}+1}xdx\]
OpenStudy (anonymous):
lol. let u=2x^2+1
OpenStudy (anonymous):
or be a wise guy and write as
\[e\int e^{2x^2}xdx\]
OpenStudy (anonymous):
ignore me, do what sparkles says
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Sorry for typing lol... we all have to start somewhere :)
OpenStudy (anonymous):
\(u=2x^2+1, du=4xdx, \frac{1}{4}du=xdx\)
OpenStudy (anonymous):
\[\left( e ^{2x ^{2}+1} \right)/4 + K\] ??????
OpenStudy (anonymous):
um...no.
integral e^u du where u=2x^2+! and du=4xdx
OpenStudy (anonymous):
ugh
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes and you can check that it is right by differntiating
OpenStudy (lgbasallote):
why do i have a feeling this has an imaginary error function....o.O
OpenStudy (anonymous):
which is it right or wrong lol
OpenStudy (anonymous):
@myluv4u you have the right answer
OpenStudy (anonymous):
thank you yay!!!
Join the QuestionCove community and study together with friends!
Sign Up
myininaya (myininaya):
@igbasallote I think you missed the x multiplier like I did at first
OpenStudy (anonymous):
\[\frac{1}{4}e^{2x^2+1}+C\]
OpenStudy (lgbasallote):
oh yeah..don't mid me..do what satellite and sparkles are doing :p
OpenStudy (lgbasallote):
dont mind me*
OpenStudy (anonymous):
thanks all