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base of a solid is enclosed by y=sqrt(x) y=2 and x=0 each cross-section is a semi-circle, how do I find the volume
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\[2\Pi \int\limits_{0}^{4} x dx\]
this came from 2 * pi * r^2, the area of a circle. your radius in this case was sqrt(x), so you are technically integrating 2 * pi * sqrt(x)^2.
Each cross-section is a semi-circle so the required integral would be:\[\pi \int\limits_{0}^{4}xdx\]
|dw:1334737695024:dw| you need more info on this.. are the cross sections perpendicular to the x or y axis?
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