Question

n/a

Answer 1

i said that "1 is the hights proboblity, you cant have more than 1." not sure if i am correct

Answer 2

add these probabilities, they will sum to 1

Answer 3

and when every element is covered in sample space, their probability sum will be 1

Answer 4

thanks. for the same question above i have another one. """If the simulated dice is ‘rolled’ twice, what is the probability of obtaining a
total value of 7? (Show your working.)""?

Answer 5

because for any event there is 100% chance something will happen

you can roll a die and have it land on any value other than 1 thru 6 right?
so all those possible cases have a certain probability, the sum reflects the total amount of outcomes which has to have probability of 100% since anything else is impossible
:)

Answer 6

@dumbcow you giving me more understanding thanks

Answer 7

7 can be obtained in these ways:
1,6
2,5
3,4
4,3
5,2
6,1
as they r independent events, u have to multiply teir probabilities and add the products

Answer 8

so will it be 1 + 6 = 7, 2+5 = 7 ect?

Answer 9

no..
add multiply their probabilities
probability for occuring 1: 1/6
probability for occuring 6: 1/12
so, probability to occur both: 1/6 *1/12= 1/72
similarly, have to find out probability of occuring 2,5 together, 3,4 together and so on..
finally add these products

Answer 10

i got it now!, thanks a lot

Answer 11

another question i have for the same ""Does the result above (for a total value of 7) differ from the result that would
be obtained with an unbiased dice? (Show your working.)"""