Question

Water flows with 1 gal/min and 10oF temperature difference. Calculate the ton of cooling load ?

Answer 1

So you need to cool water 10 Fahrenheit grades at 1 gallon per minute.
From the web I get
http://www.engineeringtoolbox.com/cooling-loads-d_665.html

1 refrigeration ton = 12661 kJ/h. 1000J/kJ.1hour/3600 s = 3516,94 J/s

and a (US) gallon is 3,78541E-3 m³

and the heat capacity of water = 4,18 J/kgK.1000kg/1m³ = 4180J/m³K

and for dT -> 1K = 1,8°F (for temperature differences: one degree kelvin equals 1,8 degree Fahrenheit)

so i calculate x which is the cooling load:

x = 1gal/min. 3,78541E-3m³/ 1 gal .1min/60s. 4180J/m³K.1refr ton/3516,94 J/s.10°F.10K/18°F = 4,165368E-4 refr.tons (scientific notation)
or thus
0,0004165 refr tons.