Find the integral: 1/((1-u^2)^2)

Question

anonymous · Answer

u=sin(theta)

anonymous · Answer

if u want the original problem, here it is: x=tsint y=tcost 0<=t<=1, find the Arc length

0bucchr · Answer

I would probably use partial fractions - factorize that diff of squares on the bottom

anonymous · Answer

top is already 1, not gona be usefull

anonymous · Answer

the simple one is this, after the work u get integral of sec^3(theta), that's wat im stuck on

anonymous · Answer

integrals are not my strong suit... I've always found that it's the type of thing you need to practice to get good at... As for Wolfram, it uses u = tan(x) for me when I enter the equation at first, dunno how you got hyperb sin :-S

anonymous · Answer

idk either, but it did so im confused lol

anonymous · Answer

nono, dont put the equations in, the half way worked,

anonymous · Answer

charron, put in integral of sec^3theta,, how am i suupose to get that answer=/ im pretty sure i cant nor will the teacher as me to that lol

anonymous · Answer

wow, yeah, that's a nice one lol

anonymous · Answer

im guessing wolfram is only giving his SUPER PRO answers.... oh well im fudge my quiz friday lol

0bucchr · Answer

http://www.wolframalpha.com/input/?i=integral%3A+1%2F%28%281-u%5E2%29%5E2%29 that solves the integral partial fractions then just substitution

anonymous · Answer

anser r right, but no clue, well im close this- ty for helping guys