Question

Concentrated ammonia solution contains 17.9 mol/dm^3 of ammonia.What volume of this solution is required to make 1dm^3 of a 2.0mol/dm^3 [2]

Excess calcium reacted vigorously with 25cm^3 of 1.0mol/dm^3 hydrochloric acid producing calcium chloride solution and hydrogen

a)Write a balanced chemical equation with state symbols for the reaction [3]
Ca (s)+2HCL(aq)===CaCl2+H2(g)

Describe how you would obtain dry crystals of hydrated calcium chloride, CaCl2.6H20,from the solution formed [4]

Answer 1

b)What is the maximum possible yield of hydrated calcium chloride CaCl2.6H20,from the reaction?
Ca=40 Cl=35.5 0=16

Answer 2

Help me with par b) and description part please

Answer 3

so h2o is yield from h2 with oxygen from atmosphere?

Answer 4

Concentrated ammonia solution contains 17.9 mol/dm^3 of ammonia.What volume of this solution is required to make 1dm^3 of a 2.0mol/dm^3 [2]

1 dm^3 of 2mol/dm^3 means we have 2 moles

17.9 mol/dm^3 x V dm^3 = 2 mol

\[\frac{2 \text{ }mol}{17.9 \text{ } (mol/dm^3)} = V dm^3 = 0.111731844.. \text{ } dm^3\]

Answer 5

concentration x volume = moles

Answer 6

all hydrogenchloride react with calcium, after that 2H2 from yield + O2 == 2H20, then 6H2O + CaCl2 == CaCl2.6H2O . u can put the mole of HCL in equation and get mole CaCl2.6H2O after that convert to gram with Mr CaCl2.6H2O

Answer 7

@A_Level_Student , sorry aint good with chemistry. :(

Answer 8

k no problem boss ;)