Question

Simplify: Image attached.

Answer 1

factorise both the numerator and the denominator of both the first term, and cancel out common terms after that.

Answer 2

\[\LARGE \frac{x^2-3x-18}{x^2-2x-24}\div \frac{1}{x+4}=\]
\[\LARGE \frac{(x+3)(x-6)}{(x+4)(x-6)}\div \frac{1}{x+4}=\]
\[\LARGE \frac{(x+3)}{(x+4)} \cdot (x+4)=x+3\]