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OpenStudy (0bucchr):
Laplace transformation of e^(3t+1)
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OpenStudy (amistre64):
we can split that up into a constant and a 3t part
OpenStudy (amistre64):
\[\large b^{n+m}=b^n\ b^m\]
OpenStudy (0bucchr):
do continue..
OpenStudy (amistre64):
that was pretty much it; the rest is just using the table of laplace tranforms
OpenStudy (amistre64):
\[L\{e^{3t+1}\}\to\ L\{e^{3t}e\}\to\ e\ L\{e^{et}\}\]
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OpenStudy (amistre64):
spose to be a 3t in that last part :/
OpenStudy (0bucchr):
haha thanks. I do know the answer - just testing whether questions for older people have a place here.
OpenStudy (amistre64):
;)
if i recall it correctly: L{e^at} = 1/(s-a)
OpenStudy (amistre64):
and if your browser is slowing down, try using google chrome; its spose to be the test browser for the site
OpenStudy (0bucchr):
Thanks. I'm running it now but here in the heart of africa we dont have the fastest connection
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OpenStudy (amistre64):
look for the zebra with a radio tag :)
OpenStudy (0bucchr):
haha. Have you heard about Wolfram Alpha?
OpenStudy (0bucchr):
if I write an answer do I get a medal? e/(s-3)
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