Laplace transformation of e^(3t+1)
we can split that up into a constant and a 3t part
\[\large b^{n+m}=b^n\ b^m\]
do continue..
that was pretty much it; the rest is just using the table of laplace tranforms
\[L\{e^{3t+1}\}\to\ L\{e^{3t}e\}\to\ e\ L\{e^{et}\}\]
spose to be a 3t in that last part :/
haha thanks. I do know the answer - just testing whether questions for older people have a place here.
;) if i recall it correctly: L{e^at} = 1/(s-a)
and if your browser is slowing down, try using google chrome; its spose to be the test browser for the site
Thanks. I'm running it now but here in the heart of africa we dont have the fastest connection
look for the zebra with a radio tag :)
haha. Have you heard about Wolfram Alpha?
if I write an answer do I get a medal? e/(s-3)
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