One second, i am trying to attach the pictures of the problem
tag me when u get it
http://imgur.com/pZZAS is the problem http://imgur.com/sSsvL is the solution I just need it explained better.
use the product rule for one and the quotient rule for the other
since a derivative measures the slope at a point; the derivative of a line is the same at every point .... so the derivatives individually are the slope at the given ... thing
so, what are they doing with the graph?
the graph are of lines; so you can determine the derivative of f and g individually by taking the slope of the line at the point
what point?
the derivative of y=mx+b is simply ... m
yes, i know that
I am sorry if i am asking stupid questions, but this problem just has gotten me flustered
well, it says u'(1) and v'(5) so im gonna go out on a limb and say they want them when x=1 for the first part; and x=5 for the other part
first find u' and v' using the product rule and the quotient rule
u = fg u' = f'g + fg' u'(1) = f'(1) g(1) + f(1) g'(1)
the graph gives you all the pertinent information to fill those in
v = f/g v' = (gf'-fg')/g^2 and use the point x=5 for that one
when you say use point five, where would 5 go in that equation?
functions need not be defined as equation; the graphs they present define the functions; so you have to take this to a geometry mindset
when x=5; what value, from the graph, do f and g have? what are the slopes of f and g when x=5?
same idea for the other part; but when x=1
I will try and solve the problem, and if i get stuck again, i will post here
k the info you need is: f(5) = g(5) = f'(5) = slope of f at x=5 = g'(5) = slope of g at x=5 = f(1) = g(1) = f'(1) = slope of f at x=1 = g'(1) = slope of g at x=1 = then fill those into the derivative rules to determine the answers
ok, thx
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